# Problem

You are given N integers. Sort the N integers and print the sorted order.
Store the N integers in a vector. Vectors are sequence containers representing arrays that can change in size.

Declaration :

```vector<int>v; (creates an empty vector of integers)
```

Size :

```int size=v.size();
```

Pushing an integer into a vector :

```v.push_back(x);(where x is an integer.The size increases by 1 after this.)
```

Popping the last element from the vector :

```v.pop_back(); (After this the size decreases by 1)
```

Sorting a vector :

```sort(v.begin(),v.end()); (Will sort all the elements in the vector)
```

### Input Format :

The first line of the input contains N where N is the number of integers. The next line contains N integers.

### Constraints :

• 1 <= N <= 10^5
• 1<= Vi <= 10^9, where Vi is the ith integer in the Vertex

### Output Format :

Print the integers in the sorted order one by one in a single line followed by a space.

```5
1 6 10 8 4
```

### Sample Output :

`1 4 6 8 10`

### Vector-Sort in C++ – Hacker Rank Solution

```#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
/* Vector-Sort in C++ - Hacker Rank Solution Start */
int n,i;
cin >> n;
vector<int> numbers(n, 0);
for(i = 0; i < n; i++)
{
cin >> numbers[i];
}
sort(numbers.begin(), numbers.end());
for(i = 0; i < n; i++)
{
cout << numbers[i] << " ";
}
/* Vector-Sort in C++ - Hacker Rank Solution End */
return 0;
}```

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