# Total Expenses Codechef Solution

Hello coders, today we are going to solve Total Expenses CodeChef Solution whose Problem Codes is FLOW009.

### Problem

While purchasing certain items, a discount of 10% is offered if the quantity purchased is more than 1000.

If the quantity and price per item are input, write a program to calculate the total expenses.

### Input

The first line contains an integer T, total number of test cases. Then follow T lines, each line contains integers quantity and price.

### Output

For each test case, output the total expenses while purchasing items, in a new line.

### Constraints

• 1 <= T <= 1000
• 1 <= quantity, price <= 100000

```3
100 120
10 20
1200 20
```

### Output

```12000.000000
200.000000
21600.000000
```

### Total Expenses CodeChef Solution in Python

```for i in range(int(input())):
total = 0
m, n = map(int, input().split())
total += (m * n)
if m > 1000:
discount = total - (total * 10/100)
print(discount)
else:
print(total)```

### Total Expenses CodeChef Solution in CPP

```#include <iostream>
using namespace std;
int main() {
int t;
double e,f,p,d;
cin>>t;
while(t--){
cin>>e>>f;
p = e*f;
if(e>1000){
d=p/10;
p-=d;
printf("%f\n",p);
}
else{
printf("%f\n",p);
}
}
return 0;
}```

### Total Expenses CodeChef Solution in JAVA

```import java.util.*;
import java.lang.*;
import java.io.*;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int TEST = sc.nextInt();
while(TEST-->0)
{
int a=sc.nextInt();
int b=sc.nextInt();
float dis=a*b;
if(a>1000)
{
dis=dis-(dis/10);
System.out.println(dis);
}
else
{
System.out.println(dis);
}
}
}
}```

Disclaimer: The above Problem (Total Expensesis generated by CodeChef but the solution is provided by Chase2learn.This tutorial is only for Educational and Learning purpose.

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