# Students Marks Sum – Hacker Rank Solution

You are given an array of integers, marks, denoting the marks scored by students in a class.

• The alternating elements marks0marks2marks4, and so on denote the marks of boys.
• Similarly, marks1marks3marks5, and so on denote the marks of girls.

The array name marks, works as a pointer which stores the base address of that array. In other words, marks contains the address where marks0 is stored in the memory.For example, let marks = [3,2,5] and marks stores 0x7fff9575c05f. Then, 0x7fff9575c05f is the memory address of marks0.

Complete the function, `marks_summation(int* marks, char gender, int number_of_students)` which returns the total sum of:

• marks of boys if gender = b
• marks of girl if gender = g

The locked code stub reads the elements of marksalong with gender. Then, it calls the function `marks_summation(marks, gender, number_of_students)` to get the sum of alternate elements as explained above and then prints the sum.

#### Input Format

• The first line contains number_of_students, denoting the number of students in the class, hence the number of elements in marks.
• Each of the number_of_students subsequent lines contains marksi.
• The next line contains gender.

#### Constraints

• number_of_students <=10^3
• 1<=marksi<=10^3(where 0<= i< number_of_students)
• gender = g or b

#### Output Format

The output should contain the sum of all the aternate elements in marks as explained above.

```3
3
2
5
b
```

```8
```

#### Explanation 0

marks = [3,2,5] andgender = b.
somarks0+marks2 = 3+5 = 8.

```5
1
2
3
4
5
g
```

```6
```

#### Explanation 1

marks = [1,2,3,4,5] andgender = g.
so Sum = marks1+marks3 = 2+5 = 8.

```1
5
g
```

```0
```

#### Explanation 2

marks =  andgender = g.
here does marks1 not exist. so Sum = 0

### Students Marks Sum – Hacker Rank Solution

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
//Complete the following function.
int marks_summation(int* marks, int number_of_students, char gender)
{
//Write your code here.
int sum = 0;
for (int i = (gender == 'b' ? 0 : 1); i < number_of_students; i = i + 2)
sum += *(marks + i);
return sum;
}
int main() {
int number_of_students;
char gender;
int sum;
scanf("%d", &number_of_students);
int *marks = (int *) malloc(number_of_students * sizeof (int));
for (int student = 0; student < number_of_students; student++) {
scanf("%d", (marks + student));
}
scanf(" %c", &gender);
sum = marks_summation(marks, number_of_students, gender);
printf("%d", sum);
free(marks);
return 0;
}```

Disclaimer: The above Problem (Students Marks Sum ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.