Strings in C++ – Hacker Rank Solution

Strings in C++ - Hacker Rank Solution
Strings in C++ – Hacker Rank Solution


C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:

string a = "abc";


int len = a.size();

Concatenate two strings:

string a = "abc";
string b = "def";
string c = a + b; // c = "abcdef".

Accessing i th element:

string s = "abc";
char   c0 = s[0];   // c0 = 'a'
char   c1 = s[1];   // c1 = 'b'
char   c2 = s[2];   // c2 = 'c'
s[0] = 'z';         // s = "zbc"

P.S.: We will use cin/cout to read/write a string.

Input Format

You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters (‘a’-‘z’).

Output Format

In the first line print two space-separated integers, representing the length of a and b, respectively.In the second line print the string produced by concatenating a and b(a+b).In the third line print two strings separated by a space, a’ and b’.a’ and b’ are the same as a and b, respectively, except that their first characters are swapped.

Sample Input :


Sample Output :

4 2
ebcd af

Explanation :

  •  = “abcd”
  •  = “ef”
  • |a| = 4
  • |b| = 2
  • a+b = “abcdef”
  • a’ = “ebcd”
  • b’ = “af”

Strings in C++ – Hacker Rank Solution

#include <iostream>
#include <string>
using namespace std;
int main()
    string str1,str2,str3;
    char b,a;
    int strlen1,strlen2;
    //string one
    //string two
    //first string size
    strlen1 = str1.size();
    //second string size
    strlen2 = str2.size();
    cout<<" "<<strlen2;
    // concatinate two string
    str3 = str1+str2;
    // a' b'
    a = str2[0];
    b = str1[0];
    str1[0] = a;
    str2[0] = b;
    cout<<" "<<str2;
    return 0;

Disclaimer: The above Problem (Strings in C++ – Hacker Rank Solution ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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