Problem
C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:
Declaration:
string a = "abc";
Size:
int len = a.size();
Concatenate two strings:
string a = "abc"; string b = "def"; string c = a + b; // c = "abcdef".
Accessing i th element:
string s = "abc"; char c0 = s[0]; // c0 = 'a' char c1 = s[1]; // c1 = 'b' char c2 = s[2]; // c2 = 'c' s[0] = 'z'; // s = "zbc"
P.S.: We will use cin/cout to read/write a string.
Input Format
You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters (‘a’-‘z’).
Output Format
In the first line print two space-separated integers, representing the length of a and b, respectively.In the second line print the string produced by concatenating a and b(a+b).In the third line print two strings separated by a space, a’ and b’.a’ and b’ are the same as a and b, respectively, except that their first characters are swapped.
Sample Input :
abcd ef
Sample Output :
4 2 abcdef ebcd af
Explanation :
- a = “abcd”
- b = “ef”
- |a| = 4
- |b| = 2
- a+b = “abcdef”
- a’ = “ebcd”
- b’ = “af”
Strings in C++ – Hacker Rank Solution
#include <iostream>
#include <string>
using namespace std;
int main()
{
string str1,str2,str3;
char b,a;
int strlen1,strlen2;
//string one
cin>>str1;
//string two
cin>>str2;
//first string size
strlen1 = str1.size();
//second string size
strlen2 = str2.size();
cout<<strlen1;
cout<<" "<<strlen2;
// concatinate two string
str3 = str1+str2;
cout<<"\n"<<str3;
// a' b'
a = str2[0];
b = str1[0];
str1[0] = a;
str2[0] = b;
cout<<"\n";
cout<<str1;
cout<<" "<<str2;
return 0;
}Disclaimer: The above Problem (Strings in C++ – Hacker Rank Solution ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.
