# Sale Season Codechef Solution

Hello coders, today we are going to solve Sale Season Codechef Solutions whose Problem Code is SALESEASON.

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## Problem

It’s the sale season again and Chef bought items worth a total of X rupees. The sale season offer is as follows:

Find the final amount Chef needs to pay for his shopping.

### Input Format

• The first line of input will contain a single integer T, denoting the number of test cases.
• Each test case consists of single line of input containing an integer X.

### Output Format

For each test case, output on a new line the final amount Chef needs to pay for his shopping.

### Constraints

• 1 ≤ T ≤ 100
1 ≤ X ≤ 10000

Input

```4
15
70
250
1000```

Output

```15
70
225
975```

### Explanation:

Test case 11: Since X \le 100X≤100, there is no discount.

Test case 33: Here, X = 250X=250. Since 100 \lt 250 \le 1000100<250≤1000, discount is of 2525 rupees. Therefore, Chef needs to pay 250-25 = 225250−25=225 rupees.

### Sale Season Codechef Solution in JAVA

```/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
for(int i=0; i<T; i++)
{
int N = sc.nextInt();
double r = 0;
for(int j=0; j<N; j++)
{
int p = sc.nextInt();
int q = sc.nextInt();
int d = sc.nextInt();
double pp = p+((double)p*d)/100;
pp = pp-(pp*d)/100;
r=r+(p-pp)*q;
}
System.out.println(r);
}
}
}```

### Sale Season Codechef Solution in CPP

``` #include <iostream>
using namespace std;
int main() {
int t;
cin>>t;
while(t--){
int n;
cin>>n;
double sum=0;
for(int i=1;i<=n;i++){
double p,x,d;
cin>>p>>x>>d;
double dis=double(d)/100;
double finalp=p+(p*dis);
double finalfp=finalp-(finalp*dis);
double loss=x*(p-finalfp);
sum+=loss;
}
cout<<fixed<<sum<<endl;
}
return 0;
}```

### Sale Season Codechef Solution in Python

```for testcases in range(int(input())):
a=int(input())
count=0
for i in range(a):
a,b,c=map(int,input().split())
d=a*b
a+=(0.01*c*a)
a-=(0.01*a*c)
a*=b
count+=(d-a)
print(float(count))```

Disclaimer: The above Problem (Sale Season ) is generated by CodeChef but the solution is provided by  Chase2learn.This tutorial is only for Educational and Learning purpose.

Finally, we are now, in the end, I just want to conclude some important message for you

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