Ruby Blocks HackerRank Solution

Hello coders, In this post, you will learn how to solve Ruby Blocks HackerRank Solution. This problem is a part of the Ruby Tutorial series. One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions.

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Ruby Blocks HackerRank Solution

Let’s get started with Ruby Blocks HackerRank

Problem Statement

Higher order functions are one of the key components of functional programming.

A higher order function is a tool that takes other functions as parameters or returns them as a result.

Blocks are nameless methods that can be passed to another method as a parameter.
Passing a block to a method is a great way of data abstraction.

Blocks can either be defined with a keyword do ... end or curly braces { ... }.

Example:

_{a). Passing a block to a method that takes no parameter}

_CODE

def call_block
puts “Start of method.”
yield
puts “End of method.“
end
call_block do
puts “I am inside call_block method.”
end

_OUTPUT

Start of method.
I am inside call_block method.
End of method.

In this example, a block is passed to the call_block method.
To invoke this block inside the method, we used a keyword, yield.
Calling yield will execute the code within the block that is provided to the method.

_{b). Passing a block to a method that takes one or more parameters.}

_CODE

def calculate(a,b)
yield(a, b)
end

puts calculate(15, 10) {|a, b| a – b}

_OUTPUT

In this example, we have defined a method calculate that takes two parameters a and b. The yield statement invokes the block with parameters a and b, and executes it.

Task

You are given a partially complete code. Your task is to fill in the blanks (_).

The factorial method computes: n! { n x n – 1 x . . . 2 x 1 }.

Ruby Blocks HackerRank Solution

def factorial
  yield
end
n = gets.to_i
factorial do 
  puts (1..n).inject(:*)
end

Note: This problem (Ruby Blocks HackerRank) is generated by HackerRank but the solution is provided by Chase2Learn. This tutorial is only for Educational and Learning purpose.