# Reverse The Number Codechef Solution

Hello coders, today we are going to solve Reverse The Number CodeChef Solution.

## Problem

Given an Integer N, write a program to reverse it.

## Input

The first line contains an integer T, total number of testcases. Then follow T lines, each line contains an integer N.

## Output

For each test case, display the reverse of the given number N, in a new line.

## Constraints

• 1 <= T <= 1000
• 1 <= N <= 1000000

Input:

```4
12345
31203
2123
2300
```

Output:

```54321
30213
3212
32```

## Reverse The Number– CodeChef Solution in Python

```for _ in range(int(input())):
N = int(input())
Rev = 0
while N > 0:
Rev = Rev * 10 + N % 10
N = N // 10
print(Rev) ```

## Reverse The Number– CodeChef Solution in CPP

```#include<bits/stdc++.h>
using namespace std;
int main(){
int a,c,ck=0,n,i,cc,dd,rem=0,rev=0,j=1;
cin>>n;
for(i=0; i<n; i++){
cin>>a;
while(a!=0){
rem = a%10;
rev = rev*10 + rem;
a/=10;
}
cout<<rev<<endl;
rev=0;
}
}```

## Reverse The Number– CodeChef Solution in JAVA

```import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
for (int tc = 0; tc < T; tc++) {
int N = sc.nextInt();
System.out.println(solve(N));
}
sc.close();
}
static int solve(int N) {
return Integer.parseInt(new StringBuilder(String.valueOf(N)).reverse().toString());
}
}```

Disclaimer: The above Problem (Reverse The Number) is generated by CodeChef but the solution is provided by Chase2learn.This tutorial is only for Educational and Learning purpose.