Hello coders, In this post, you will learn how to solve Regex Substitution in Python HackerRank Solution. This problem is a part of the Python Hacker Rank series.
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Regex Substitution in Python HackerRank Solution
problem
The re.sub() tool (sub stands for substitution) evaluates a pattern and, for each valid match, it calls a method (or lambda).
The method is called for all matches and can be used to modify strings in different ways.
The re.sub() method returns the modified string as an output.
Learn more about re.sub()
Transformation of Strings
Code :
import re
#Squaring numbers
def square(match):
number = int(match.group(0))
return str(number**2)
print re.sub(r"\d+", square, "1 2 3 4 5 6 7 8 9")
Output :
1 4 9 16 25 36 49 64 81
Replacements in Strings :
Code :
import re
html = """
<head>
<title>HTML</title>
</head>
<object type="application/x-flash"
data="your-file.swf"
width="0" height="0">
<!-- <param name="movie" value="your-file.swf" /> -->
<param name="quality" value="high"/>
</object>
"""
print re.sub("(<!--.*?-->)", "", html) #remove comment
Output :
<head> <title>HTML</title> </head> <object type="application/x-flash" data="your-file.swf" width="0" height="0"> <param name="quality" value="high"/> </object>
Task :
You are given a text of N lines. The text contains && and || symbols.
Your task is to modify those symbols to the following:
&& → and || → or
Both && and || should have a space ” ” on both sides.
Input Format :
The first line contains the integer, N.
The next N lines each contain a line of the text.
Constraints :
- 0 < N < 100
- Neither
&&nor||occur in the start or end of each line.
Output Format :
Output the modified text.
Sample Input :
11
a = 1;
b = input();
if a + b > 0 && a - b < 0:
start()
elif a*b > 10 || a/b < 1:
stop()
print set(list(a)) | set(list(b))
#Note do not change &&& or ||| or & or |
#Only change those '&&' which have space on both sides.
#Only change those '|| which have space on both sides.
Sample Output :
a = 1;
b = input();
if a + b > 0 and a - b < 0:
start()
elif a*b > 10 or a/b < 1:
stop()
print set(list(a)) | set(list(b))
#Note do not change &&& or ||| or & or |
#Only change those '&&' which have space on both sides.
#Only change those '|| which have space on both sides.Regex Substitution in Python HackerRank Solution
import re
def change(match):
if match.group(1) == '&&':
return 'and'
else:
return 'or'
for _ in range(int(input())):
print(re.sub(r"(?<= )(\|\||&&)(?= )", change,input()))Disclaimer: The above Problem (Regex Substitution in Python – HackerRank Solution) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.
FAQ:
Does HackerRank have Python?
HackerRank’s programming challenges can be solved in a variety of programming languages (including Java, C++, PHP, Python, SQL, JavaScript) and span multiple computer science domains.
Where can I practice Python coding?
- HackerRank is a great site for practice that’s also interactive.
Where can I find HackerRank solutions in Python?
in this post, you will get all the solutions to HackerRank Python Problems.
Is possible HackerRank Solution in Python?
HackerRank’s programming challenges can be solved in a variety of programming languages (including Java, C++, PHP, Python, SQL, and JavaScript) and span multiple computer science domains. When a programmer submits a solution to a programming challenge, their submission is scored on the accuracy of their output.
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