Puppy and Sum Codechef Solution

Hello coders, today we are going to solve Puppy and Sum Codechef Solution Which is part of Codechef.

Puppy and Sum Codechef Solution
Puppy and Sum Codechef Solution

Problem

Yesterday, puppy Tuzik learned a magically efficient method to find the sum of the integers from 1 to N. He denotes it as sum(N). But today, as a true explorer, he defined his own new function: sum(D, N), which means the operation sum applied D times: the first time to N, and each subsequent time to the result of the previous operation.

For example, if D = 2 and N = 3, then sum(2, 3) equals to sum(sum(3)) = sum(1 + 2 + 3) = sum(6) = 21.

Tuzik wants to calculate some values of the sum(D, N) function. Will you help him with that?

Input

The first line contains a single integer T, the number of test cases. Each test case is described by a single line containing two integers D and N.

Output

For each testcase, output one integer on a separate line.

Constraints

  • 1 <= T <= 16
  • 1 <= D, N <= 4

Example

Input:

2
1 4
2 3

Output:

10
21

Explanation 

The first test case: sum(1, 4) = sum(4) = 1 + 2 + 3 + 4 = 10.

The second test case: sum(2, 3) = sum(sum(3)) = sum(1 + 2 + 3) = sum(6) = 1 + 2 + 3 + 4 + 5 + 6 = 21.

Puppy and Sum CodeChef Solution in Python

T = int(input())
for _ in range(T):
    a, b = map(int, input().split())
    for i in range(0, a):
        b = (b *(b +1)) // 2
    print(b)

Puppy and Sum CodeChef Solution in CPP

#include <iostream>
using namespace std;
int main() {
    int t,n,k,instanceMax,maxx=0;
    cin>>t;
    while(t--){
        cin>>n>>k;
        maxx=0;
        for(int i=1;i<=k;i++){
            instanceMax = n%i;
            if(instanceMax > maxx){
                maxx = instanceMax;
            }
        }
        cout<<maxx<<endl;
    }
    return 0;

Puppy and Sum CodeChef Solution in JAVA

import java.io.FileNotFoundException;
import java.util.Scanner;
public class Main {
    public static void main(String[] args) throws FileNotFoundException {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-- > 0) {
            int n = sc.nextInt();
            int k = sc.nextInt();
            int maxMod = -1;
            int j = 1;
            while(j <= k) { // go from 1 till k
                if(n%j > maxMod) {
                    maxMod = n%j;
                }
                j++;
            }
            System.out.println(maxMod);
        }
        sc.close();
    }
}

Disclaimer: The above Problem (Puppy and Sum) is generated by CodeChef but the solution is provided by Chase2learn.This tutorial is only for Educational and Learning purpose.

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