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## Polar Coordinates in Python HackerRank Solution

### problem

Polar coordinates are an alternative way of representing Cartesian coordinates or Complex Numbers.

A complex number z

is completely determined by its real part x and imaginary part y.

Here, j is the imaginary unit.

A polar coordinate (r, q)is completely determined by modulus r and phase angle q.

if we convert complex number z to its polar coordinate, we find:r : Distance from z to origin, i.e., √(x^2+y^2)

q : Counter clockwise angle measured from the positive x-axis to the line segment that joins z to the origin.

Python’s cmath module provides access to the mathematical functions for complex numbers.**cmath.phase**This tool returns the phase of complex number z(also known as the argument of z).

>>> phase(complex(-1.0,0.0))3.1415926535897931

**abs**This tool returns the modulus (absolute value) of complex number z.

>>> abs(complex(-1.0,0.0))1.0

#### Task :

You are given a complex z. Your task is to convert it to polar coordinates.

#### Input Format :

A single line containing the complex number z. Note: complex() function can be used in python to convert the input as a complex number.

#### Constraints :

Given number is a valid complex number

#### Output Format :

Output two lines:

The first line should contain the value of r.

The second line should contain the value of q.

#### Sample Input :

1+2j

#### Sample Output :

2.236067977499791.1071487177940904

### Polar Coordinates in Python HackerRank Solution

# Python 3 # Polar Coordinates in Python - Hacker Rank Solution # Enter your code here. Read input from STDIN. Print output to STDOUT # Polar Coordinates in Python - Hacker Rank Solution START import cmath; num = complex(input()) z = complex(num) print(cmath.polar(z)[0]) print(cmath.polar(z)[1]) # Polar Coordinates in Python - Hacker Rank Solution END

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#### Where can I find HackerRank solutions in Python?

in this post, you will get all the *solutions* to *HackerRank Python* Problems.

#### Is possible HackerRank Solution in Python?

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