Pointers in C – Hacker Rank Solution

Pointer in C
Pointers in C – Hacker Rank Solution


In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer in C is a way to share a memory address among different contexts (primarily functions). They are primarily used whenever a function needs to modify the content of a variable, of which it doesn’t have ownership.
In order to access the memory address of a variable,val, we need to prepend it with & sign. E.g., &val returns the memory address of val.
This memory address is assigned to a pointer and can be shared among various functions. E.g. int *p = &val will assign the memory address of val to pointer p. To access the content of the memory to which the pointer points, prepend it with a *. For example, *p will return the value reflected by val and any modification to it will be reflected at the source (val).

1 2 3 4 5 6 7 8 9 10void increment(int *v) { (*v)++; } int main() { int a; scanf(“%d”, &a); increment(&a); printf(“%d”, a); return 0; }


You have to complete the function void update(int *a,int *b), which reads two integers as argument, and sets a with the sum of them, and b with the absolute difference of them.– a` = a+b
– b` = |a-b| 

Input Format

The input will contain two integers, a and b, separated by a newline.

Output Format

You have to print the updated value of a and b on two different lines.Note: Input/ouput will be automatically handled. You only have to complete the function described in the ‘task’ section.

Pointers in C – Hacker Rank Solution

#include <stdio.h>
#include <stdlib.h>
void update(int *a,int *b)
    // Pointers in C - Hacker Rank Solution START
    int x,y;
    x = *a + *b;
    y = *a - *b;
    *a = x;
    *b =abs(y);
    // Pointers in C - Hacker Rank Solution END
int main()
    int a, b;
    int *pa = &a, *pb = &b;
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);
    return 0;

Disclaimer: The above Problem (Pointers in C) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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