Plus One Leetcode Solution

In this post, we are going to solve the Plus One Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.

Table of Contents

Problem

You are given a large integer represented as an integer array digits, where each digits[i] is the i^th digit of the integer. The digits are ordered from most significant to least significant in left–to-right order. The large integer does not contain any leading 0‘s.

Increment the large integer by one and return the resulting array of digits.

Example 1:

Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].

Example 2:

Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].

Example 3:

Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].

Constraints:

1 <= digits.length <= 100
0 <= digits[i] <= 9

digits does not contain any leading 0‘s.

Now, let’s see the leetcode solution of Plus One Leetcode Solution.

Plus One Leetcode Solution in Python

class Solution(object):
    def plusOne(self, digits):
        string =""
        result =[]
        for d in digits:
            string += str(d)
        i = int(string) + 1
        for w in str(i):
            result.append(w)
        return result

Plus One Leetcode Solution in CPP

class Solution {
public:
    vector<int> plusOne(vector<int>& digits) {
        int len = digits.size();
        for(int i=len-1; i>=0; i--){
            if(digits[i] != 9){
                digits[i]+=1;
                return digits;
            }else{
                digits[i] = 0;
            }
        }
        vector<int> arr(len+1);
        arr.insert(arr.begin(), 1);
        
        return arr;
    }
};

Plus One Leetcode Solution in Java

class Solution {
    public int[] plusOne(int[] digits) {
        int len = digits.length;
        for(int i=len-1; i>=0; i--){
            if(digits[i] != 9){
                digits[i]+=1;
                return digits;
            }else{
                digits[i] = 0;
            }
        }
        int[] arr = new int[len+1];
        arr[0] = 1;
        
        return arr;
    }
}

Note: This problem Plus One is generated by Leetcode but the solution is provided by Chase2learn This tutorial is only for Educational and Learning purposes.

NOTE: Add Binary Leetcode Solution