# Overload Operators in C++ Hacker Rank Solution

Hello coders, In this post, you will learn how to solve the Overload Operators in C++ Hacker Rank Solution. This problem is a part of the HackerRank C++ Programming Series.

## Overload Operators in C++ Hacker Rank Solution

### Objective

You are given a class – Complex.

```class Complex
{
public:
int a,b;
};
```

Operators are overloaded by means of operator functions, which are regular functions with special names. Their name begins with the operator keyword followed by the operator sign that is overloaded. The syntax is:

```type operator sign (parameters) { /*... body ...*/ }
```

You need to overload operators + and << for the Complex class.
The operator + should add complex numbers according to the rules of complex addition:

```(a+ib)+(c+id) = (a+c) + i(b+d)
```

Overload the stream insertion operator << to add “a+ib” to the stream:

```cout<<c<<endl;
```

The above statement should print “a+ib” followed by a newline where a = c.a and b = c.b .

#### Input Format :

The overloaded operator + should receive two complex numbers ( a+ib and c+id) as parameters. It must return a single complex number.
The overloaded operator << should add “a+ib” to the stream where a is the real part and b is the imaginary part of the complex number which is then passed as a parameter to the overloaded operator.

```3+i4
5+i6
```

`8+i10`

### Overload Operators in C++ Hacker Rank Solution

```#include<iostream>
using namespace std;
class Complex
{
public:
int a,b;
void input(string s)
{
int v1=0;
int i=0;
while(s[i]!='+')
{
v1=v1*10+s[i]-'0';
i++;
}
while(s[i]==' ' || s[i]=='+'||s[i]=='i')
{
i++;
}
int v2=0;
while(i<s.length())
{
v2=v2*10+s[i]-'0';
i++;
}
a=v1;
b=v2;
}
};
//Overload operators + and << for the class complex
//+ should add two complex numbers as (a+ib) + (c+id) = (a+c) + i(b+d)
//<< should print a complex number in the format "a+ib"
/* Overload Operators in C++ - Hacker Rank Solution START */
Complex operator+(const Complex X, const Complex Y)
{
Complex Z;
Z.a = X.a + Y.a;
Z.b = X.b + Y.b;
return Z;
}
ostream& operator<<(ostream& os, const Complex C)
{
return os << C.a << "+" << "i" << C.b;
}
/* Overload Operators in C++ - Hacker Rank Solution END */
int main()
{
Complex x,y;
string s1,s2;
cin>>s1;
cin>>s2;
x.input(s1);
y.input(s2);
Complex z=x+y;
cout<<z<<endl;
}
```

Disclaimer: The above Problem (Overload Operators in C++ ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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