Hello coders, today we are going to solve Number of Credits Codechef Solution whose Problem Code is CREDS.
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Number of Credits Codechef Solution
Problem
Chef has a binary string S. He can modify it by choosing any subsequence of length 3 from it and deleting the first and last character of the subsequence.
For example, if S = textcolor{red}{11}01textcolor{red}{0}1S=110101, Chef can choose the subsequence marked in red and delete its first and last characters, obtaining the string S = 1011S=1011.
Chef wonders what is the lexicographically largest string he can obtain by modifying the original string using a finite number of operations. Please help Chef in this task.
Note: A binary string AA is said to be lexicographically larger than another binary string BB if:
- BB is a proper prefix of AA (for example, 101101 is lexicographically larger than 1010); or
- There exists an index ii such that A_1 = B_1, A_2 = B_2, ldots, A_{i-1} = B_{i-1}A1=B1,A2=B2,…,Ai−1=Bi−1 and A_i gt B_iAi>Bi.
Input Format
- The first line of input will contain a single integer TT, denoting the number of test cases.
- Each test case consists of a single line of input containing the original binary string SS.
Output Format
For each test case, output on a new line the lexicographically largest string Chef can obtain.
Constraints
- 1 leq T leq 2cdot 10^41≤T≤2⋅104
- 3 leq |S| leq 10^53≤∣S∣≤105
- SS is a binary string, i.e, only contains the characters 00 and 11 in it
- The sum of |S|∣S∣ over all test cases won’t exceed 3cdot 10^53⋅105.
Sample 1:
Input
4 101 1010 0000 0001
Output
101 11 0000 0
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Explanation:
Test case 11: It is optimal to not perform any moves.
Test case 22: In one move, by choosing the subsequence 1textcolor{red}{010}1010, the string can be made into 1111, which is the lexicographically largest possible.
Test case 33: It is optimal to not perform any move.
Number of Credits Codechef Solution in CPP
#include <iostream> using namespace std; int main() { // your code goes here int t; cin>>t; while(t--) { int x,y,z; cin>>x>>y>>z; int a=x*4; int b=y*2; cout<<a+b<<endl; } return 0; }
Number of Credits Codechef Solution in JAVA
/* package codechef; // don't place package name! */ import java.util.*; import java.lang.*; import java.io.*; /* Name of the class has to be "Main" only if the class is public. */ class Codechef { public static void main (String[] args) throws java.lang.Exception { Scanner Sc=new Scanner(System.in); int T= Sc.nextInt(); for(int i=1;i<=T;i++){ int X= Sc.nextInt(); int Y= Sc.nextInt(); int Z= Sc.nextInt(); System.out.println(4*X+ 2*Y + 0*Z); } } }
Number of Credits Codechef Solution in Python
# cook your dish here T=int(input()) for i in range(T): x,y,z=map(int,input().split(' ')) print(x*4+y*2)
Disclaimer: The above Problem (Number of Credits) is generated by CodeChef but the solution is provided by Chase2learn.This tutorial is only for Educational and Learning purpose.
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