Java If-Else – Hacker Rank Solution

Java If-Else - Hacker Rank Solution
Java If-Else – Hacker Rank Solution

Problem

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Java If-Else - Hacker Rank Solution

Task

Given an integer, n, perform the following conditional actions:

  • If n is odd, print Weird
  • If n is even and in the inclusive range of 2 to 5, print Not Weird
  • If n is even and in the inclusive range of 6 to 20 , print Weird
  • If n is even and greater than 20, print Not Weird

Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer, n.

Constraints

1<=n<=100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.


Example 0 :-

Sample Input 0

3

Sample Output 0

Weird

Example 1 :-

Sample Input 1

24

Sample Output1

Not Weird

Explanation

Sample Case 0: n=3n is odd and odd numbers are weird, so we print Weird.Sample Case 1:n=24 n>24 and n is even, so it isn’t weird. Thus, we print Not Weird.



Java If-Else – Hacker Rank Solution

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class Solution
{
    private static final Scanner scanner = new Scanner(System.in);
    public static void main(String[] args)
 {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        if(N%2!=0)
        {
            System.out.println("Weird");
        }
        else if(N >=2&&N<=5)
        {
            System.out.println("Not Weird");
        }
        else if(N>=6 && N <= 20)
        {
            System.out.println("Weird");
        }
        else if(N>=20)
        {
            System.out.println("Not Weird");
        }
        scanner.close();
    }
}

Disclaimer: The above Problem (Java If-Else ) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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