Java Exception Handling Try-catch Hacker Rank Solution

Hello coders, In this post, you will learn how to solve Java Exception Handling Try-catch Hacker Rank Solution. This problem is a part of the Java programming series. 

One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions.

Java Exception Handling Try-catch Hacker Rank Solution

Objective

Exception handling is the process of responding to the occurrence, during computation, of exceptions – anomalous or exceptional conditions requiring special processing – often changing the normal flow of program execution.

Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if y is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.

Sample Input 0:

10
3

Sample Output 0:

3

Sample Input 1:

10
Hello

Sample Output 1:

java.util.InputMismatchException

Sample Input 2:

10
0

Sample Output 2:

java.lang.ArithmeticException: / by zero

Sample Input 3:

23.323
0

Sample Output 3:

java.util.InputMismatchException

Java Exception Handling Try-catch Hacker Rank Solution

import java.util.Scanner;
class MyCalculator {
    long power(int n, int p) throws Exception {
        if (n < 0 || p < 0) {
            throw new Exception("n or p should not be negative.");
        } else if (n == 0 && p == 0) {
            throw new Exception("n and p should not be zero.");
        }
        return (long) Math.pow(n, p);
    }
}
public class Solution {
    public static final MyCalculator my_calculator = new MyCalculator();
    public static final Scanner in = new Scanner(System.in);
    public static void main(String[] args) {
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}

Disclaimer: The above Problem (Java Exception Handling Try-catch) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.