Java Arraylist Hacker Rank Solution

Hello coders, In this post, you will learn how to solve Java Arraylist Hacker Rank Solution. This problem is a part of the Java programming series. One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions.

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Java Arraylist Hacker Rank Solution
Java Arraylist – Hacker Rank Solution

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Java Arraylist Hacker Rank Solution


Sometimes it’s better to use dynamic size arrays. Java’s Arraylist can provide you this feature. Try to solve this problem using Arraylist.

You are given  lines. In each line there are zero or more integers. You need to answer a few queries where you need to tell the number located in  position of  line.

Take your input from

Input Format
The first line has an integer . In each of the next  lines there will be an integer  denoting number of integers on that line and then there will be  space-separated integers. In the next line there will be an integer  denoting number of queries. Each query will consist of two integers  and .


Each number will fit in signed integer.
Total number of integers in  lines will not cross .

Output Format
In each line, output the number located in  position of  line. If there is no such position, just print “ERROR!”

Sample Input

5 41 77 74 22 44
1 12
4 37 34 36 52
3 20 22 33
1 3
3 4
3 1
4 3
5 5

Sample Output



The diagram below explains the queries:

Java Arraylist Hacker Rank Solution

Java Arraylist Hacker Rank Solution

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class Solution {
	public static void main(String[] args) {
		Scanner in = new Scanner(;
		List<List<Integer>> lines = new ArrayList<List<Integer>>();
		int n = in.nextInt();
		for (int i = 0; i < n; i++) {
			List<Integer> line = new ArrayList<Integer>();
			int d = in.nextInt();
			for (int j = 0; j < d; j++) {
		int q = in.nextInt();
		for (int i = 0; i < q; i++) {
			int x = in.nextInt();
			int y = in.nextInt();
			if (y > lines.get(x - 1).size()) {
			} else {
				System.out.println(lines.get(x - 1).get(y - 1));

Disclaimer: The above Problem (Java Arraylist) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.


1. HackerRank Java All Problems Solutions

Hackerrank java problems solutions with practical program code examples and step-by-step full complete explanation.

2. Can HackerRank learn Java?

Welcome to the world of Java! In this challenge, we practice printing to stdout. The code stubs in your editor declare a Solution class and the main method. 

3. What is HackerRank Java test?

The HackerRank Skills Certification Test is a standardized assessment to help developers prove their coding skills.

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These certificates are useless, and you should not put them on your resume. The experience you gained from getting them is not useless. Use it to build a portfolio, and link to it on your resume. 

5. Can I retake HackerRank test?

The company which sent you the HackerRank Test invite owns your Test submissions and results. It’s their discretion to permit a reattempt for a particular Test. If you wish to retake the test, we recommend that you contact the concerned recruiter who invited you to the Test and request a re-invite

6. Can I learn Java per month?

you can’t master it in 1 month, it needs continuous hard work and experience. JAVA is a vast language even developers don’t know fully. you go in-depth about each particular class in java. Java is such a platform which have been used in all platform like android, web, and cloud so keep working on your interest. 

Where can I find HackerRank solutions in Java?

in this post you will get all the solutions of HackerRank java Problems.

Finally, we are now, in the end, I just want to conclude some important message for you

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