itertools.combinations() in Python – HackerRank Solution

itertools combinations in python hacker rank solution
itertools.combinations() in Python – HackerRank Solution

itertools.combinations(iterable, r)
This tool returns the r length subsequences of elements from the input iterable.
Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order.

Sample Code :

>>> from itertools import combinations
>>>
>>> print list(combinations('12345',2))
[('1', '2'), ('1', '3'), ('1', '4'), ('1', '5'), ('2', '3'), ('2', '4'), ('2', '5'), ('3', '4'), ('3', '5'), ('4', '5')]
>>>
>>> A = [1,1,3,3,3]
>>> print list(combinations(A,4))
[(1, 1, 3, 3), (1, 1, 3, 3), (1, 1, 3, 3), (1, 3, 3, 3), (1, 3, 3, 3)]

Task :

You are given a string S.
Your task is to print all possible combinations, up to size k, of the string in lexicographic sorted order.


Input Format :

A single line containing the string S and integer value k separated by a space.

Constraints :

  • 0 < k <= len(S)

The string contains only UPPERCASE characters.

Output Format :

Print the different combinations of string S on separate lines.


Sample Input :

HACK 2

Sample Output :

A
C
H
K
AC
AH
AK
CH
CK
HK

itertools.combinations() in Python – HackerRank Solution

# itertools.combinations() in Python - Hacker Rank Solution
# Python 3
# Enter your code here. Read input from STDIN. Print output to STDOUT
# itertools.combinations() in Python - Hacker Rank Solution START
from itertools import combinations
io = input().split()
S = io[0]
k = int(io[1])
for i in range(1,k+1):
    for j in combinations(sorted(S),i):
        print("".join(j))

Disclaimer: The above Problem (itertools.combinations() in Python) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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