Hello Programmers, In this post, you will learn how to solve HackerRank Making Anagrams Solution. This problem is a part of the HackerRank Algorithms Series.
One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions. We are going to solve the HackerRank Algorithms problems using C, CPP, JAVA, PYTHON, JavaScript & SCALA Programming Languages.
HackerRank Making Anagrams Solution
Task
We consider two strings to be anagrams of each other if the first string‘s letters can be rearranged to form the second string. In other words, both strings must contain the same exact letters in the same exact frequency. For example, bacdc and dcbac are anagrams, but bacdc and dcbad are not.
Alice is taking a cryptography class and finding anagrams to be very useful. She decides on an encryption scheme involving two large strings where encryption is dependent on the minimum number of character deletions required to make the two strings anagrams. Can you help her find this number?
Given two strings, s1 and s2, that may not be of the same length, determine the minimum number of character deletions required to make s1 and s2 anagrams. Any characters can be deleted from either of the strings.
Example
s1 = abc
s2 = amnop
The only characters that match are the a‘s so we have to remove bc from s1 and mnop from s2 for a total of 6 deletions.
Function Description
Complete the makingAnagrams function in the editor below.
makingAnagrams has the following parameter(s):
- string s1: a string
- string s2: a string
Returns
- int: the minimum number of deletions needed
Input Format
The first line contains a single string, s1.
The second line contains a single string, s2.
Constraints
- 1 <= |s1|, |s2| <= 104
- It is guaranteed that s1 and s2 consist of lowercase English letters, ascii[a–z].
Sample Input
cde
abc
Sample Output
4
Explanation
Delete the following characters from our two strings to turn them into anagrams:
- Remove
dandefromcdeto getc. - Remove
aandbfromabcto getc.
characters have to be deleted to make both strings anagrams.
HackerRank Making Anagrams Solution
HackerRank Making Anagrams Solution in C
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
char str1[20000];
char str2[20000];
scanf("%s", str1);
scanf("%s", str2);
int n1 = strlen(str1);
int n2 = strlen(str2);
int i, j;
char s1[26] = {0};
for (i = 0; i < n1; ++i) {
s1[str1[i] - 97] += 1;
}
for (i = 0; i < n2; ++i) {
s1[str2[i] - 97] -= 1;
}
int count = 0;
for (i = 0; i < 26; ++i) {
count += abs(s1[i]);
}
printf("%d\n", count);
return 0;
}HackerRank Making Anagrams Solution in Cpp
#include <cmath>
#include <cstring>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
char s1[10010],s2[10010];
cin>>s1>>s2;
int a[26]={0};
for(int i=0;i<strlen(s1);i++)
a[s1[i]-'a']++;
for(int i=0;i<strlen(s2);i++)
a[s2[i]-'a']--;
long long int ans = 0;
for(int i=0;i<26;i++)
ans += abs(a[i]);
cout<<ans<<endl;
return 0;
}HackerRank Making Anagrams Solution in Java
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN.
Print output to STDOUT. Your class should be named Solution. */
Scanner in = new Scanner(System.in);
String src = (in.nextLine());
String tar = in.nextLine();
int length = 0;
Map<Character, Integer> an= new HashMap <Character, Integer>();
for ( int i=0; i< src.length(); i++){
char c = src.charAt(i);
if (an.containsKey(c) )
an.put(c, an.get(c)+1);
else
an.put(c, 1);
}
for ( int j=0; j< tar.length(); j++){
char c = tar.charAt(j);
if (an.containsKey(c) && an.get(c)!= 0 ) {
an.put(c,an.get(c) -1);
length+=2;
}
}
System.out.println(src.length() + tar.length()- length );
}
}HackerRank Making Anagrams Solution in Python
w1=raw_input()
w2=raw_input()
total=0
for letter in "abcdefghijklmnopqrstuvwxyz":
total+=abs(w1.count(letter)-w2.count(letter))
print totalHackerRank Making Anagrams Solution using JavaScript
var processData, solve;
processData = function(input) {
var A, B, answer, _ref;
_ref = input.split('\n'), A = _ref[0], B = _ref[1];
answer = solve(A, B);
console.log(answer);
return answer;
};
solve = function(A, B) {
var hash, i, key, sum, _i, _j, _ref, _ref1;
hash = {};
A = A.split('');
for (i = _i = 0, _ref = A.length; 0 <= _ref ? _i < _ref : _i > _ref; i = 0 <= _ref ? ++_i : --_i) {
if (A[i] in hash) {
hash[A[i]] += 1;
} else {
hash[A[i]] = 1;
}
}
for (i = _j = 0, _ref1 = B.length; 0 <= _ref1 ? _j < _ref1 : _j > _ref1; i = 0 <= _ref1 ? ++_j : --_j) {
if (B[i] in hash) {
hash[B[i]] -= 1;
} else {
hash[B[i]] = -1;
}
}
sum = 0;
for (key in hash) {
sum += Math.abs(hash[key]);
}
return sum;
};
process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
_input += input;
});
process.stdin.on("end", function () {
processData(_input);
});HackerRank Making Anagrams Solution in Scala
import java.util.Scanner
object Solution {
def main(args: Array[String]) {
val sc = new Scanner(System.in);
val n1 = sc.nextLine().toList.groupBy(e => e).map(e => (e._1, e._2.size)).withDefaultValue(0)
val n2 = sc.nextLine().toList.groupBy(e => e).map(e => (e._1, e._2.size)).withDefaultValue(0)
var minDel = 0
for (key <- n1.keySet ++ n2.keySet) {
minDel += Math.max(n1(key), n2(key)) - Math.min(n1(key), n2(key))
}
System.out.println(minDel)
}
}HackerRank Making Anagrams Solution in Pascal
{$H+}
uses math;
const
tfi='';
tfo='';
var
fi,fo:text;
n,t:longint;
a,b:string;
d1,d2:array['a'..'z'] of longint;
procedure nhap;
var i:longint;
begin
readln(fi,a);
readln(fi,b);
end;
procedure process;
var i,j,tg:longint;
ch:char;
begin
for i:=1 to length(a) do inc(d1[a[i]]);
for i:=1 to length(b) do inc(d2[b[i]]);
for ch:='a' to 'z' do
t:=t+max(d1[ch],d2[ch])-min(d1[ch],d2[ch]);
writeln(fo,t);
end;
BEGIN
assign(fi,tfi);reset(fi);
assign(fo,tfo);rewrite(fo);
nhap;
process;
close(fi);close(fo);
END.
Disclaimer: This problem (Making Anagrams) is generated by HackerRank but the solution is provided by Chase2learn. This tutorial is only for Educational and Learning purposes.
