HackerRank Chocolate Feast Solution

Hello Programmers, In this post, you will learn how to solve HackerRank Chocolate Feast Solution. This problem is a part of the HackerRank Algorithms Series.

One more thing to add, don’t straight away look for the solutions, first try to solve the problems by yourself. If you find any difficulty after trying several times, then look for the solutions. We are going to solve the HackerRank Algorithms problems using C, CPP, JAVA, PYTHON, JavaScript & SCALA Programming Languages.

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HackerRank Chocolate Feast Solution
HackerRank Chocolate Feast Solution

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HackerRank Chocolate Feast

Task

Little Bobby loves chocolate. He frequently goes to his favorite 5 & 10 store, Penny Auntie, to buy them. They are having a promotion at Penny Auntie. If Bobby saves enough wrappers, he can turn them in for a free chocolate.

Example

n = 15
c = 3
m = 2

He has 15 to spend, bars cost 3, and he can turn in 2 wrappers to receive another bar. Initially, he buys 5 bars and has 5 wrappers after eating them. He turns in 4 of them, leaving him with 1, for 2 more bars. After eating those two, he has 3 wrappers, turns in 2 leaving him with 1 wrapper and his new bar. Once he eats that one, he has 2 wrappers and turns them in for another bar. After eating that one, he only has  wrapper, and his feast ends. Overall, he has eaten 5 + 2 + 1 + 1 = 9 bars.

Function Description

Complete the chocolateFeast function in the editor below.

chocolateFeast has the following parameter(s):

  • int n: Bobbys initial amount of money
  • int c: the cost of a chocolate bar
  • int m: the number of wrappers he can turn in for a free bar

Returns

  • int: the number of chocolates Bobby can eat after taking full advantage of the promotion

Note: Little Bobby will always turn in his wrappers if he has enough to get a free chocolate.

Input Format

The first line contains an integer, t, the number of test cases to analyze.
Each of the next t lines contains three space-separated integers: nc, and m. They represent money to spend, cost of a chocolate, and the number of wrappers he can turn in for a free chocolate.

Constraints

  • 1 <= t <= 1000
  • 2 <= n <= 105
  • 1 <= c <= n
  • 2 <= m <= n

Sample Input

STDIN Function
—– ——–
3 t = 3 (test cases)
10 2 5 n = 10, c = 2, m = 5 (first test case)
12 4 4 n = 12, c = 4, m = 4 (second test case)
6 2 2 n = 6, c = 2, m = 2 (third test case)

Sample Output

6
3
5

Explanation

Bobby makes the following  trips to the store:

  1. He spends 10 on 5 chocolates at 2 apiece. He then eats them and exchanges all 5 wrappers to get 1 more. He eats 6 chocolates.
  2. He spends his 12 on 3 chocolates at 4 apiece. He has 3 wrappers, but needs 4 to trade for his next chocolate. He eats 3 chocolates.
  3. He spends 6 on 3 chocolates at 2 apiece. He then exchanges 2 of the 3 wrappers for 1 additional piece. Next, he uses his third leftover chocolate wrapper from his initial purchase with the wrapper from his trade-in to do a second trade-in for 1 more piece. At this point he has 1 wrapper left, which is not enough to perform another tradein. He eats 5 chocolates.

HackerRank Chocolate Feast Solution

Chocolate Feast Solution in C

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

    int t, n, c, m;
    scanf("%d", &t);
    while ( t-- )
    {
    scanf("%d%d%d",&n,&c,&m);
        n/=c;
        int k = n;
        while (n >= m )
        {
             k++,n-=(m-1);   
        }
        printf("%d\n",k);
    }
    return 0;
}

Chocolate Feast Solution in Cpp

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */   
    int t,n,c,m;
    cin>>t;
    while(t--){
        cin>>n>>c>>m;
        int ans=0;
        ans+=n/c;
        int x=n/c;
        while(x>=m){
            ans+=x/m;
            x=x/m+x%m;
        }
        cout<<ans<<endl;
    }
    return 0;
}

Chocolate Feast Solution in Java

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        for(int i = 0; i < t; i++){
            System.out.println(f(in.nextInt(), in.nextInt(), in.nextInt()));
        }
    }
    
    private static long f(int n, int a, int b){
        return n/a + g(n/a, b);
    }
    
    private static long g(int a, int b){
        if(a < b) return 0;
        else return a/b + g(a-a/b*b + a/b, b);
    }
}

Chocolate Feast Solution in Python

T = int(raw_input())
for t in xrange(T):
    N, C, M = [int(e) for e in raw_input().strip().split()]
    chocolates = 0
    wrappers = 0
    while N >= C:
        nc = N // C
        N -= (nc * C)
        chocolates += nc
        wrappers += nc
    while wrappers >= M:
        wr = wrappers // M
        wrappers -= M * wr
        wrappers += wr
        chocolates += wr
    print chocolates

Chocolate Feast Solution using JavaScript

function processData(input) {
    input = input.trim();
    var lines = input.split("\n");
    var T = parseInt(lines[0]);
    for(var i = 1; i <= T;i++){
        var data = lines[i].split(" ");
        var N = parseInt(data[0]);
        var M = parseInt(data[2]);
        var C = parseInt(data[1]);
        var total = Math.floor(N/C);
        var add = Math.floor(total/M);
        
        var sum = add;
        add += total%M;
        while(add >= M){
            var cho = Math.floor(add/M);
            add = cho + add%M;
            sum += cho;
        }
        
        
        console.log(total+sum);
    }    
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});

Chocolate Feast Solution in Scala

import scala.io._

object Solution {

	val in = new In(Source.stdin)
	
	def main(args: Array[String]): Unit = 
	{
		val testCount = in().toInt
		for (_ <- 1 to testCount)
		{
			val N, C, M = in().toInt
			
			var cho = N/C
			var wrap = cho
			
			while (wrap >= M)
			{
				cho += wrap/M 
				wrap = wrap%M + wrap/M
			}
			
			println(cho)
		}
	}
}

class TokenIterator(iter: BufferedIterator[Char], delims: String) extends Iterator[String]
{	
	private val sb = new StringBuilder
	def hasNext: Boolean = {
		skipDelims()
		iter.hasNext
	}
	def skipDelims() {
		while (iter.hasNext && delims.indexOf(iter.head) != -1) {
			iter.next()
		}
	}
	def next(): String = {
		skipDelims()
		while (iter.hasNext && delims.indexOf(iter.head) == -1) {
			sb.append(iter.next())
		}
		val ret = sb.toString()
		sb.clear()
		ret
	}
}

class In(source: Source) {
	val iter = source.buffered
	val tokenIterator = new TokenIterator(iter, " \r\n")
	val lineIterator = new TokenIterator(iter, "\r\n")
	def apply() = tokenIterator.next() // lineIterator.next()
	def apply(n: Int) = lineIterator.take(n)
}

Chocolate Feast Solution in Pascal

var tt,ii,n,m,c,w,res,tmp:longint;
var settled:boolean;
begin
    read(tt);
    for ii:=1 to tt do begin
        read(n,c,m);
        settled:=false;
        res:=0;
        w:=0;
        while not(settled) do begin
            settled:=true;
            if n>=c then begin
                settled:=false;
                tmp:=trunc(n/c);
                inc(res,tmp);
                n:=n mod c;
                inc(w,tmp);
            end;
            if w>=m then begin
                settled:=false;
                tmp:=trunc(w/m);
                inc(res,tmp);
                w:=w mod m;
                inc(w,tmp);
            end;
        end;
        writeln(res);
    end;
end.

Disclaimer: This problem (Chocolate Feast) is generated by HackerRank but the solution is provided by Chase2learn. This tutorial is only for Educational and Learning purposes.

FAQ:

1. How do you solve the first question in HackerRank?

If you want to solve the first question of Hackerrank then you have to decide which programing language you want to practice i.e C programming, Cpp Programing, or Java programming then you have to start with the first program HELLO WORLD.

2. How do I find my HackerRank ID?

You will receive an email from HackerRank to confirm your access to the ID. Once you have confirmed your email, the entry will show up as verified on the settings page. You will also have an option to “Make primary”. Click on that option. Read more

3. Does HackerRank detect cheating?

yes, HackerRank uses a powerful tool to detect plagiarism in the candidates’ submitted code. The Test report of a candidate highlights any plagiarized portions in the submitted code and helps evaluators to verify the integrity of answers provided in the Test.

4. Does HackerRank use camera?

No for coding practice Hackerrank does not use camera but for companies’ interviews code submission time Hackerrank uses the camera.

5. Should I put HackerRank certificate on resume?

These certificates are useless, and you should not put them on your resume. The experience you gained from getting them is not useless. Use it to build a portfolio, and link to it on your resume. 

6. Can I retake HackerRank test?

The company which sent you the HackerRank Test invite owns your Test submissions and results. It’s their discretion to permit a reattempt for a particular Test. If you wish to retake the test, we recommend that you contact the concerned recruiter who invited you to the Test and request a re-invite. 

7. What is HackerRank?

HackerRank is a tech company that focuses on competitive programming challenges for both consumers and businesses. Developers compete by writing programs according to provided specifications. Wikipedi


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