For Loop in C – Hacker Rank Solution

For Loop in C - Hacker Rank Solution
For Loop in C – Hacker Rank Solution

Objective

In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be repeatedly executed.
The syntax for this is

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>
  • expression_1 is used for initializing variables which are generally used for controlling the terminating flag for the loop.
  • expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
  • expression_3 is generally used to update the flags/variables

A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Task

For each integer n in the interval [a,b] (given as input) :

  •  If 1<= n , then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
  • Else if n > 9 and it is an even number, then print “even”.
  • Else if n < 9 and it is an odd number, then print “odd”.

Input Format

The first line contains an integer, a.The second line contains an integer, b.

Constraints :-

1<=a<=b<=10^6

Output Format

Print the appropriate English representation,even, or odd, based on the conditions described in the ‘task’ section.


Sample Input

8
11

Sample Output

eight
nine
even
odd





For Loop in C – Hacker Rank Solution

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main()
{
    int a, b;
    scanf("%d\n%d", &a, &b);
   // Complete the code.
   // For Loop in C - Hacker Rank Solution START
    char *str[] = {"one", "two", "three", "four", "five", "six", "seven",  "eight",  "nine", "even", "odd"};
    scanf("%d\n%d", &a, &b);
    for (int i=a; i<=b; i++)// i= 8
    {
            if (i <= 9)
        {
                printf ("%s\n", str[i-1]);
        }
            else
        {
                printf ("%s\n", str[9+(i%2)]);
        }
    // For Loop in C - Hacker Rank Solution END
    }
    return 0;
}

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