Day 7: Regular Expressions III | 10 Days of JavaScript – Hacker Rank Solution

Day 7: Regular Expressions III | 10 Days of JavaScript – Hacker Rank Solution: Hey Guy’s In this post we are solving Day 7: Regular Expressions III which is a part of 10 Days of JavaScript Series.

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Complete the function in the editor below by returning a RegExp object, re, that matches every integer in some string s.

Constraints

• The length of string s is >= 3.
• It’s guaranteed that string s contains at least one integer.

Output Format

The function must return a RegExp object that matches every integer in some string s.

Sample Input 0

102, 1948948 and 1.3 and 4.5

Sample Output 0

102

1948948

1

3

4

5

Explanation 0

When we call match on string s and pass the correct RegExp as our argument, it returns the following array of results: `[ '102', '1948948', '1', '3', '4', '5' ]`.

Sample Input 1

1 2 3

Sample Output 1

1

2

3

Explanation 1

When we call match on string s and pass the correct RegExp as our argument, it returns the following array of results: `[ '1', '2', '3' ]`.

Day 7: Regular Expressions III | 10 Days of JavaScript – Hacker Rank Solution

```'use strict';
process.stdin.resume();
process.stdin.setEncoding('utf-8');
let inputString = '';
let currentLine = 0;
process.stdin.on('data', inputStdin => {
inputString += inputStdin;
});
process.stdin.on('end', _ => {
inputString = inputString.trim().split('\n').map(string => {
return string.trim();
});
main();
});
return inputString[currentLine++];
}
function regexVar() {
/*
* Declare a RegExp object variable named 're'
* It must match ALL occurrences of numbers in a string.
*/
/*
* Do not remove the return statement
*/
return new RegExp('\\d+', 'g');
}
function main() {
const re = regexVar();
const r = s.match(re);
for (const e of r) {
console.log(e);
}
}```

Disclaimer: The above Problem (Day 7: Regular Expressions III) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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