Day 7: Regular Expressions III | 10 Days of JavaScript – Hacker Rank Solution: Hey Guy’s In this post we are solving Day 7: Regular Expressions III which is a part of 10 Days of JavaScript Series.
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Task
Complete the function in the editor below by returning a RegExp object, re, that matches every integer in some string s.
Constraints
- The length of string s is >= 3.
- It’s guaranteed that string s contains at least one integer.
Output Format
The function must return a RegExp object that matches every integer in some string s.
Sample Input 0
102, 1948948 and 1.3 and 4.5
Sample Output 0
102
1948948
1
3
4
5
Explanation 0
When we call match on string s and pass the correct RegExp as our argument, it returns the following array of results: [ '102', '1948948', '1', '3', '4', '5' ]
.
Sample Input 1
1 2 3
Sample Output 1
1
2
3
Explanation 1
When we call match on string s and pass the correct RegExp as our argument, it returns the following array of results: [ '1', '2', '3' ]
.
Day 7: Regular Expressions III | 10 Days of JavaScript – Hacker Rank Solution
'use strict'; process.stdin.resume(); process.stdin.setEncoding('utf-8'); let inputString = ''; let currentLine = 0; process.stdin.on('data', inputStdin => { inputString += inputStdin; }); process.stdin.on('end', _ => { inputString = inputString.trim().split('\n').map(string => { return string.trim(); }); main(); }); function readLine() { return inputString[currentLine++]; } function regexVar() { /* * Declare a RegExp object variable named 're' * It must match ALL occurrences of numbers in a string. */ /* * Do not remove the return statement */ return new RegExp('\\d+', 'g'); } function main() { const re = regexVar(); const s = readLine(); const r = s.match(re); for (const e of r) { console.log(e); } }
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10 days of javascript hackerrank
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