Copy List with Random Pointer Leetcode Solution

In this post, we are going to solve the Copy List with Random Pointer Leetcode Solution problem of Leetcode. This Leetcode problem is done in many programming languages like C++, Java, and Python.

Table of Contents

Problem

A linked list of length n is given such that each node contains an additional random pointer, which could point to any node in the list, or null.

Construct a deep copy of the list. The deep copy should consist of exactly n brand new nodes, where each new node has its value set to the value of its corresponding original node. Both the next and random pointer of the new nodes should point to new nodes in the copied list such that the pointers in the original list and copied list represent the same list state. None of the pointers in the new list should point to nodes in the original list.

For example, if there are two nodes X and Y in the original list, where X.random --> Y, then for the corresponding two nodes x and y in the copied list, x.random --> y.

Return the head of the copied linked list.

The linked list is represented in the input/output as a list of n nodes. Each node is represented as a pair of [val, random_index] where:

val: an integer representing Node.val
random_index: the index of the node (range from 0 to n-1) that the random pointer points to, or null if it does not point to any node.

Your code will only be given the head of the original linked list.

Example 1:

Input: head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]

Example 2:

Input: head = [[1,1],[2,1]]
Output: [[1,1],[2,1]]

Example 3:

Input: head = [[3,null],[3,0],[3,null]]
Output: [[3,null],[3,0],[3,null]]

Constraints:

0 <= n <= 1000
-10⁴ <= Node.val <= 10⁴

Node.random is null or is pointing to some node in the linked list.

Now, let’s see the leetcode solution of Copy List with Random Pointer Leetcode Solution.

Copy List with Random Pointer Leetcode Solution in Python

class Solution:
  def copyRandomList(self, head: 'Node') -> 'Node':
    if not head:
      return None
    if head in self.map:
      return self.map[head]

    newNode = Node(head.val)
    self.map[head] = newNode
    newNode.next = self.copyRandomList(head.next)
    newNode.random = self.copyRandomList(head.random)
    return newNode

  map = {}

Copy List with Random Pointer Leetcode Solution in CPP

class Solution {
 public:
  Node* copyRandomList(Node* head) {
    if (head == nullptr)
      return nullptr;
    if (map.count(head))
      return map[head];

    Node* newNode = new Node(head->val);
    map[head] = newNode;
    newNode->next = copyRandomList(head->next);
    newNode->random = copyRandomList(head->random);
    return newNode;
  }

 private:
  unordered_map<Node*, Node*> map;
};

Copy List with Random Pointer Leetcode Solution in Java

class Solution {
  public Node copyRandomList(Node head) {
    if (head == null)
      return null;
    if (map.containsKey(head))
      return map.get(head);

    Node newNode = new Node(head.val);
    map.put(head, newNode);
    newNode.next = copyRandomList(head.next);
    newNode.random = copyRandomList(head.random);
    return newNode;
  }

  private Map<Node, Node> map = new HashMap<>();
}

Note: This problem Copy List with Random Pointer is generated by Leetcode but the solution is provided by Chase2learn This tutorial is only for Educational and Learning purpose.