collections.Counter() in Python – Hacker Rank Solution

Collection.counter in Python
collections.Counter() in Python – Hacker Rank Solution

collections.Counter()
A counter is a container that stores elements as dictionary keys, and their counts are stored as dictionary values.

Sample Code

>>> from collections import Counter
>>>
>>> myList = [1,1,2,3,4,5,3,2,3,4,2,1,2,3]
>>> print Counter(myList)
Counter({2: 4, 3: 4, 1: 3, 4: 2, 5: 1})
>>>
>>> print Counter(myList).items()
[(1, 3), (2, 4), (3, 4), (4, 2), (5, 1)]
>>>
>>> print Counter(myList).keys()
[1, 2, 3, 4, 5]
>>>
>>> print Counter(myList).values()
[3, 4, 4, 2, 1]

Task :

Raghu is a shoe shop owner. His shop has X number of shoes. He has a list containing the size of each shoe he has in his shop. There are N number of customers who are willing to pay xi amount of money only if they get the shoe of their desired size. Your task is to compute how much money Raghu earned.


Input Format :

The first line contains X, the number of shoes.
The second line contains the space separated list of all the shoe sizes in the shop.
The third line contains N, the number of customers.
The next N lines contain the space separated values of the shoe size desired by the customer and xi, the price of the shoe.

Constraints :

  • 0 <= X <= 10^3
  • 0 <= N <= 10^3
  • 20 <= xi <= 100
  • 2 <= shoe size <= 20

Output Format :

Print the amount of money earned by Raghu.


Sample Input :

10
2 3 4 5 6 8 7 6 5 18
6
6 55
6 45
6 55
4 40
18 60
10 50

Sample Output :

200

Explanation :

Customer 1: Purchased size 6 shoe for $55.
Customer 2: Purchased size 6 shoe for $45.
Customer 3: Size 6 no longer available, so no purchase.
Customer 4: Purchased size 4 shoe for $40.
Customer 5: Purchased size 18 shoe for $60.
Customer 6: Size 10 not available, so no purchase.Total money earned = 55+45+40+60 = $200


collections.Counter() in Python – Hacker Rank Solution

# Enter your code here. Read input from STDIN. Print output to STDOUT
from collections import Counter
num_shoes = int(input())
shoe_sizes = Counter(map(int, input().split()))
num_customers = int(input())
cost = 0
for _ in range(num_customers):
    size, price = map(int, input().split())
    if shoe_sizes[size]:
        cost += price
        shoe_sizes[size] -= 1
print(cost)

Disclaimer: The above Problem (collections.Counter() in Python) is generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.

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