# Check Strict Superset in Python HackerRank Solution

Hello coders, In this post, you will learn how to solve Check Strict Superset in Python HackerRank Solution. This problem is a part of the Python Hacker Rank series.

## Check Strict Superset in Python HackerRank Solution

### problem

You are given a set A and n other sets.
Your job is to find whether set A is a strict superset of each of the N sets.
Print True, if A is a strict superset of each of the N sets. Otherwise, print False.
A strict superset has at least one element that does not exist in its subset.
Example
Set ([1, 3, 4]) is a strict superset of set ([1, 3]).
Set ([1, 3, 4]) is not a strict superset of set ([1, 3, 4]).
Set ([1, 3, 4]) is not a strict superset of set ([1, 3, 5]).

#### Input Format :

The first line contains the space separated elements of set A.
The second line contains integer n, the number of other sets.
The next n lines contains the space separated elements of the other sets.

#### Constraints :

• 0 < len(set(A)) < 501
• 0 < N < 21
• 0 < len(other set) < 101

#### Output Format :

Print True if set A is a strict superset of all other N sets. Otherwise, print False.

#### Sample Input :

```1 2 3 4 5 6 7 8 9 10 11 12 23 45 84 78
2
1 2 3 4 5
100 11 12
```

```False
```

#### Explanation :

Set A is the strict superset of the set ([1, 2, 3, 4, 5]) but not of the set ([100, 11, 12]) because 100 is not in set A. Hence, the output is False.

### Check Strict Superset in Python HackerRank Solution

```# Check Strict Superset in Python - Hacker Rank Solution
# Python 3
# Enter your code here. Read input from STDIN. Print output to STDOUT
# Check Strict Superset in Python - Hacker Rank Solution START
storage = set(input().split())
N = int(input())
output = True
for i in range(N):
storage2 = set(input().split())
if not storage2.issubset(storage):
output = False
if len(storage2) >= len(storage):
output = False
print(output)
# Check Strict Superset in Python - Hacker Rank Solution END
```

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