Hello coders, In this post, you will learn how to solve Check Strict Superset in Python HackerRank Solution. This problem is a part of the Python Hacker Rank series.
Check Strict Superset in Python HackerRank Solution
problem
You are given a set A and n other sets.
Your job is to find whether set A is a strict superset of each of the N sets.
Print True, if A is a strict superset of each of the N sets. Otherwise, print False.
A strict superset has at least one element that does not exist in its subset.
Example
Set ([1, 3, 4]) is a strict superset of set ([1, 3]).
Set ([1, 3, 4]) is not a strict superset of set ([1, 3, 4]).
Set ([1, 3, 4]) is not a strict superset of set ([1, 3, 5]).
Input Format :
The first line contains the space separated elements of set A.
The second line contains integer n, the number of other sets.
The next n lines contains the space separated elements of the other sets.
Constraints :
- 0 < len(set(A)) < 501
- 0 < N < 21
- 0 < len(other set) < 101
Output Format :
Print True if set A is a strict superset of all other N sets. Otherwise, print False.
Sample Input :
1 2 3 4 5 6 7 8 9 10 11 12 23 45 84 78 2 1 2 3 4 5 100 11 12
Sample Output :
False
Explanation :
Set A is the strict superset of the set ([1, 2, 3, 4, 5]) but not of the set ([100, 11, 12]) because 100 is not in set A. Hence, the output is False.
Check Strict Superset in Python HackerRank Solution
# Check Strict Superset in Python - Hacker Rank Solution
# Python 3
# Enter your code here. Read input from STDIN. Print output to STDOUT
# Check Strict Superset in Python - Hacker Rank Solution START
storage = set(input().split())
N = int(input())
output = True
for i in range(N):
storage2 = set(input().split())
if not storage2.issubset(storage):
output = False
if len(storage2) >= len(storage):
output = False
print(output)
# Check Strict Superset in Python - Hacker Rank Solution END
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