Hello coders, In this post, you will learn how to solve the Challenges SQL Hacker Rank Solution. This problem is a part of the SQL Hacker Rank series.
As you already know that this site does not contain only the Hacker Rank solutions here, you can also find the solution for other problems. I.e. Web Technology, Data Structures, RDBMS Programs, Java Programs Solutions, Fiverr Skills Test answers, Google Course Answers, Linkedin Assessment, and Coursera Quiz Answers.
Julia asked her students to create some coding challenges. Write a query to print the hacker_id, name, and the total number of challenges created by each student. Sort your results by the total number of challenges in descending order. If more than one student created the same number of challenges, then sort the result by hacker_id. If more than one student created the same number of challenges and the count is less than the maximum number of challenges created, then exclude those students from the result.
The following tables contain challenge data:
- Hackers: The hacker_id is the id of the hacker, and name is the name of the hacker.
- Challenges: The challenge_id is the id of the challenge, and hacker_id is the id of the student who created the challenge.
Sample Input 0
Hackers Table: Challenges Table:
Sample Output 0
21283 Angela 6 88255 Patrick 5 96196 Lisa 1
Sample Input 1
Hackers Table: Challenges Table:
Sample Output 1
12299 Rose 6 34856 Angela 6 79345 Frank 4 80491 Patrick 3 81041 Lisa 1
For Sample Case 0, we can get the following details:
Students and both created challenges, but the maximum number of challenges created is so these students are excluded from the result.
For Sample Case 1, we can get the following details:
Students and both created challenges. Because is the maximum number of challenges created, these students are included in the result.
Challenges SQL Hacker Rank Solution
SELECT H.HACKER_ID, H.NAME, COUNT(C.CHALLENGE_ID) AS TOTAL FROM HACKERS H, CHALLENGES C WHERE H.HACKER_ID=C.HACKER_ID GROUP BY H.HACKER_ID, H.NAME HAVING COUNT(C.CHALLENGE_ID) IN (SELECT MAX(TOTAL) FROM (SELECT COUNT(*) AS TOTAL FROM CHALLENGES GROUP BY HACKER_ID)) OR COUNT(C.CHALLENGE_ID) IN (SELECT TOTAL FROM (SELECT COUNT(*) AS TOTAL FROM CHALLENGES GROUP BY HACKER_ID) GROUP BY TOTAL HAVING COUNT(TOTAL)=1) ORDER BY COUNT(C.CHALLENGE_ID) DESC, H.HACKER_ID;
Disclaimer: The above Problem (Challenges) generated by Hackerrank but the Solution is Provided by Chase2Learn. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.
Is HackerRank good for SQL practice?
You’ve probably heard of HackerRank before, so it should be no surprise to you that they have one of the best collections of SQL practice challenges around.
Which SQL does HackerRank use?
The HackerRank Test interface has an in-built database query editor and supports programming in Microsoft SQL, MySQL, Oracle, or DB2 databases.
What is HackerRank SQL?
Basic. Get Certificate. SQL is an industry-standard query language that works with relational databases. Unlike some earlier systems, queries are performed at the server and only the results are passed to a client. This resulted in the ability to work with large databases efficiently over a network.
How many questions are there in HackerRank for SQL?
That will also help your SQL code challenges journey
It took me a bit more than two weeks (on and off between work, workout, and taking the kid to day school, etc.) to finish all the 58 SQL challenges on the site, and I gained quite some insights from the journey (and having quite some fun doing that!).
Where can I find HackerRank solutions in SQL?
in this post, you will get all the solutions of HackerRank SQL Problems.
Finally, we are now, in the end, I just want to conclude some important message for you
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