# Bit Array in C++ – Hacker Rank Solution

### Objective

You are given four integers: N, S, P, Q. You will use them in order to create the sequence a with the following pseudo-code.

```a = S (modulo 2^31)
for i = 1 to N-1
a[i] = a[i-1]*P+Q (modulo 2^31)
```

Your task is to calculate the number of distinct integers in the sequence  a.

#### Input Format :

Four space separated integers on a single line, N, S, P, and Q respectively.

#### Output Format :

A single integer that denotes the number of distinct integers in the sequence a.

#### Constraints :

1 <= N <= 10^80 <= S,P,Q <= 2^31

#### Sample Input :

```3 1 1 1
```

```3
```

#### Explanation :

a = [1,2,3]
Hence, there are  3 different integers in the sequence.

### Bit Array in C++ – Hacker Rank Solution

```#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
/* Bit Array in C++ - Hacker Rank Solution */
uint_fast64_t po = (uint_fast64_t)(pow(2, 31));
uint_fast64_t N, S, P, Q;
cin >> N >> S >> P >> Q;
bool r = false;
uint_fast64_t c = 0;
uint_fast64_t prv = S % po;
uint_fast64_t crn = -1;
uint_fast64_t i = 1;
do
{
crn = (prv * P + Q) % po;
if (crn != prv)
{
prv = crn;
++c;
}
else
{
r = true;
}
++i;
} while (i < N && !r);
cout << c + 1 << endl;
/* Bit Array in C++ - Hacker Rank Solution */
return 0;
}
```

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