# Array Reversal in C – Hacker Rank Solution

## Problem

Given an array, of size n, reverse it.
Example: If array, arr = [1,2,3,4,5], after reversing it, the array should be, arr[5,4,3,2,1].

#### Input Format :

The first line contains an integer, n, denoting the size of the array. The next line contains n space-separated integers denoting the elements of the array.

#### Constraints :

• 1<=n<=1000
• 1<=arri<=1000, where arri is the ith element of the array.

#### Output Format :

The output is handled by the code given in the editor, which would print the array.

```6
16 13 7 2 1 12
```

#### Sample Output 0

```12 1 2 7 13 16
```

#### Explanation 0

Given array, arr = [16,13,7,2,1,12]. After reversing the array, arr = [12,1,2,7,13,16]

#### Sample Input 1

```7
1 13 15 20 12 13 2
```

#### Sample Output 1

```2 13 12 20 15 13 1
```

#### Sample Input 2

```8
15 5 16 15 17 11 5 11
```

#### Sample Output 2

`11 5 11 17 15 16 5 15 `

### Array Reversal in C – Hacker Rank Solution

```#include <stdio.h>
#include <stdlib.h>
int main()
{
int num, *arr,*arr2,i;
scanf("%d", &num);
arr = (int*) malloc(num * sizeof(int));
for(i = 0; i < num; i++) {
scanf("%d", arr + i);
}
arr2 = (int*) malloc(num * sizeof(int));
for(i=1;i<=num;i++)
{
arr2[i-1] = arr[num-i];
}
for(i = 0; i < num; i++)
printf("%d ", *(arr2 + i));
return 0;
}```

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