Hello coders, today we are going to solve Ada and crayons Codechef Solution|Problem Code: ADACRA.

### Problem

Ada has an array of N crayons, some crayons are pointing upwards and some downwards. Ada thinks that an array of crayons is beautiful if all the crayons are pointing in the same direction.

In one step you can flip any segment of consecutive crayons. After flipping a segment, all crayons pointing downwards will point upwards and visceversa

What is the minimum number of steps to make the array of crayons beautiful?

### Input

The first line of the input contains T the number of test cases. Each test case is described in one line containing a string S of N characters, the i-th character is ‘U’ if the i-th crayon is pointing upwards and ‘D’ if it is pointing downwards.

### Output

For each test case, output a single line containing the minimum number of flips needed to make all crayons point to the same direction.

• 1 ≤ T ≤ 3000
• 1 ≤ N ≤ 50

### Explanation

Example case 1. In one step we can flip all the crayons pointing downwards

### Ada and crayons CodeChef Solution in JAVA

```import java.util.Scanner;
import java.util.stream.IntStream;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
for (int tc = 0; tc < T; tc++) {
String S = sc.next();
System.out.println(solve(S));
}
sc.close();
}
static int solve(String S) {
return ((int) IntStream.range(0, S.length() - 1).filter(i -> S.charAt(i) != S.charAt(i + 1)).count() + 1) / 2;
}
}```

Disclaimer: The above Problem (Ada and crayons) is generated by CodeChef but the solution is provided by Chase2learn. .This tutorial is only for Educational and Learning purpose.

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